General Question

travelbabe24's avatar

Why can't Mg(OH)2 act as a buffer?

Asked by travelbabe24 (262points) April 5th, 2016
6 responses
“Great Question” (1points)

I’m so confused. Buffers consist of a weak acid/base and forms it’s conjugate base/acid in solution. Mg(OH)2 is a weak base, and when a strong acid is added to it, it forms it’s conjugate weak acid and water. Since it’s a conjugate acid and base, wouldn’t that make it a buffer?

I’ve been on this homework question forever and just need an explanation. Mg(OH)2 is an antacid by the way.

Topics: ,
Observing members: 0
Composing members: 0

Answers

cazzie's avatar

Buffers are matched to the pH of the solution being examined. Not always weak. A buffer solution is one which resists changes in pH when small quantities of an acid or an alkali are added to it.

http://chemwiki.ucdavis.edu/Core/Physical_Chemistry/Acids_and_Bases/Buffers

http://www.chemguide.co.uk/physical/acidbaseeqia/buffers.html

I think the second link will help you figure out your problem. It lies with the two terms of ‘equilibrium’ and ‘equilibria’. A good buffer removes some of the hydrogen ions, but not all. MgOH2 exhausts itself completely and finds ‘equilibrium’. Magnesium is not very soluble.

cazzie's avatar

Sorry, I hit send before I finished. Magnesium is a metal, not a salt.

Rarebear's avatar

@cazzie all salts are made from ionized metals

cazzie's avatar

Yes, meaning that Magnesium, Mg alone, is a metal. MgSO4 is a salt.

Metal hydroxides ionize completely when dissolved.

cazzie's avatar

Damn it, I keep loosing my place. Trying to text with my kid. Nevermind. She should have her answer now.

Answer this question

Login

or

Join

to answer.

Mobile | Desktop


Send Feedback   

`