Natural logarithm?
I have this friend who does acceleration maths. She is in the grade below me and she asked me a maths related question.
It’s concerning natural logarithm and my memory is a little rusty because I learnt this content approximately 2 years ago.
Can anyone explain to me the steps. She sent me her working out but she doesn’t understand how to get to the answer.
The question:
4e^-2x=1
Working out:
e^-2x=¼
-2x=ln(¼)—> i dont get what to do after this step
The answer is:
x=ln(2)
Note: I know that people usually don’t answer homework related questions but this is a question for a friend and it’s concerning the logic behind natural logarithm.
I would really appreciate some help.
Thank you
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