Must… resist… figuring .. it…. ou-
Ok. Let’s talk the bare minimum and then scale up from there. Earth’s escape velocity is 11.2 km/sec Figure all the energy is kinetic. So the energy required to lift one of us up there is ½ mV^2 . Assuming 70 kg mass that comes to 4.39×10^9 kg-m^2/s^2 = 4.39×10^9 N-m. (This ignores all the air, water, protection etc. I’m figuring just a body.)
How much fuel is that? For fun let’s talk gasoline. 1 US gallon contains 110,000 BTU or 1.16×10^8 Nm Dividing, we get 37.8 gallons of fuel which weighs 110 kg. So that means we need something better than gasoline.
Nukes?
Then we need fuel to lift the fuel and the fuel to lift the fuel that is lifting the fuel…
Using gravity well theory the gw of the moon is 288km/5478km -or 1/19.02 of earth so we only need 37.8/19.02 = about 2 gallons equivalent to come back to earth, plus the fuel… plus the fuel… , etc.
I think we need something like this
Jerusalem is a much easier location.
I am such a tool.